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make sure the queue stays in te same order

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the memory pool can NOT be iterated easily, since it's not a linear object.
This commit is contained in:
Thomas Göttgens 2023-12-11 15:44:32 +01:00
parent 385b29c977
commit d952da8b1e
1 changed files with 3 additions and 3 deletions
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6
src/mesh/MeshService.cpp
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@ -146,12 +146,12 @@ NodeNum MeshService::getNodenumFromRequestId(uint32_t request_id)
NodeNum nodenum = 0; NodeNum nodenum = 0;
for (int i = 0; i < toPhoneQueue.numUsed(); i++) { for (int i = 0; i < toPhoneQueue.numUsed(); i++) {
meshtastic_MeshPacket *p = toPhoneQueue.dequeuePtr(0); meshtastic_MeshPacket *p = toPhoneQueue.dequeuePtr(0);
// put it right back on the queue
toPhoneQueue.enqueue(p, 0);
if (p->id == request_id) { if (p->id == request_id) {
nodenum = p->to; nodenum = p->to;
break; // make sure to continue this to make one full loop
} }
// put it right back on the queue
toPhoneQueue.enqueue(p, 0);
} }
return nodenum; return nodenum;
} }